A hemispherical dome of a building needs to be painted. If the circumference of the base of theCome is 17.6 m, find the cost of painting it, given the cost of painting is 5 per 100 cm".

Answer:The cost of painting the hemispherical dome is 110880 unit  Step-by-step explanation:Given as for a hemispherical dome :The circumference of base = 17.6 m The cost of painting it = 5 unit per 100 cm²∵ circumference of base = circumference of circle = 2×[tex]\pi[/tex]×radiusSo ,17.6 m = 2×[tex]\pi[/tex]×radiusOr, Radius = [tex]\frac{17.6\times 7}{2\times 22}[/tex]Or, Radius = [tex]\frac{123.2}{44}[/tex] = 2.8 mOr, R = 280 cmSo, Total surface area of hemispherical dome = 3×[tex]\pi[/tex]×radius² or, Total surface area of hemispherical dome = 3×[tex]\pi[/tex]×280² Or, Total surface area of hemispherical dome = [tex]\frac{3\times 22\times 280\times 280}{7}[/tex]Or, Total surface area of hemispherical dome = [tex]\frac{5174400}{7}[/tex]∴ Total surface area of hemispherical dome = 739200 cm² Now, The cost of painting 100 cm² is 15 unitSo,   The cost of painting 739200 cm² = [tex]\frac{15\times 739200}{100}[/tex] Or, The cost of painting 739200 cm² = 110880 unitHence The cost of painting the hemispherical dome is 110880 unit  Answer