What is the function f(x)=3(x^2-8x)+10 written in vertex form

Answer:y = 3(x - 4)² - 38Step-by-step explanation:We need to complete the square on    y = 3(x² - 8x) + 10A quadratic equation is in the form of y = ax² + bx + c.  To complete the square, take half of the b term (here, the b term is -8), then square it...-8/2 = -4(-4)² = 16Now add and subtract that from the equation...y = 3(x² - 8x + 16 - 16) + 10Now pull out the -16 from the parenthesis, be careful though, there is a  multiplier of 3 in front of the parenthesis, so it come out as a positive -48y = 3(x² - 8x + 16) + 10 - 48x² - 8x + 16 is a perfect square trinomial (we did this by completing the square), so it factors to (x - 4)², and 10 - 48 = -38, so our equation becomes...y = 3(x - 4)² - 38This is now in vertex form, which is either the minimum or maximum.Vertex form is y = a(x - h)² + k, where (h, k) is the vertex.  If a > 0, then the vertex is a minimum, if a < 0, then the vertex is a maximum.Our vertex is (4, -38)