Please help me, I Am getting-28 but I do t think it is correct

Answer:-28Step-by-step explanation:[tex]-(2-2^3)^2-4 \cdot (-2)[/tex]We going to use PE(MD)(AS).So P means ( ).We do have operations to perform in the ( ).We have [tex]2-2^3[/tex] in the first set of ( ) and (-2) in the second set of ( ).There are no operations in the second  set containing -2.So we are just focusing on the [tex]2-2^3[/tex] right now.You have subtract and exponent here.Exponents come first in PE(MD)(AS) so we will perform that first.[tex]2-2^3=2-8=-6[/tex]Let's go back to the original problem now.[tex]-(2-2^3)^2-4 \cdot (-2)[/tex][tex]-(-6)^2-4 \cdot(-2)[/tex]Now there are no longer any operations grouped together by use of ( ).It on to the rest of PE(MD)(AS).So now we are doing the E part, the exponents.[tex]-(36)-4 \cdot(-2)[/tex]Now there is multiplication and subtraction left.(MD) comes before (AS) so we do the multiplication and then the subtraction.  So I'm going to do 4(-2) now:[tex]-(36)-(-8)[/tex]Subtraction is addition of the opposite so you could write:[tex]-(36)+8[/tex]We don't really need ( ) around the first number:[tex]-36+8[/tex]36-8 is 28 but since 36>8 and 36 has a negative sign on it, the answer is -28.